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NEW QUESTION: 1
Sie verwalten eine Microsoft SQL Server 2012-Datenbank mit dem Namen ContosoDb. Die Tabellen sind wie im Exponat angegeben definiert. (Klicken Sie auf die Schaltfläche "Ausstellen".)

Sie müssen Zeilen aus der Orders-Tabelle für die Customers-Zeile mit dem CustomerId-Wert 1 im folgenden XML-Format anzeigen.

Welche Transact-SQL-Abfrage sollten Sie verwenden?
A. SELECT Name, Land, OrderId, OrderDate, Betrag FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FÜR XML AUTO ELEMENTE
B. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId - Customers.CustomerId
WHERE Customers.CustomerId = 1
FÜR XML AUTO ELEMENTE
C. SELECT Name AS '@Name', Land AS '@Country', OrderId, OrderDate, Betrag FROM Orders INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML PATH ('Customers' )
D. WÄHLEN Sie den Namen ALS "Kunden / Name", das Land ALS "Kunden / Land", die Bestellnummer, das Bestelldatum und den Auftragsbetrag INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId WHERE Customers.CustomerId = 1 FOR XML PATH (' Kunden')
E. WÄHLEN Sie Name, Land, Bestell-ID, Bestelldatum, Betrag von Bestellungen
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FÜR XML AUTO
F. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FÜR XML RAW
G. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FÜR XML RAW ELEMENTE
H. SELECT OrderId, OrderDate, Amount, Name, Country FROM Orders
INNER JOIN Customers ON Orders.CustomerId = Customers.CustomerId
WHERE Customers.CustomerId = 1
FÜR XML AUTO
Answer: C

NEW QUESTION: 2
Scenario
Refer to the topology. Your company has connected the routers R1, R2, and R3 with serial links. R2 and R3 are connected to the switches SW1 and SW2, respectively. SW1 and SW2 are also connected to the routers R4 and R5.
The EIGRP routing protocol is configured.
You are required to troubleshoot and resolve the EIGRP issues between the various routers.
Use the appropriate show commands to troubleshoot the issues.









The loopback interfaces on R4 with the IP addresses of 10.4.4.4/32, 10.4.4.5/32, and 10.4.4.6/32 are not appearing in the routing table of R5. Why are the interfaces missing?
A. R4 has been incorrectly configured to be in another AS, so it does not peer with R5.
B. The loopback addresses haven't been advertised, and the network command is missing on R4.
C. The interfaces are shutdown, so they are not being advertised.
D. Automatic summarization is enabled, so only the 10.0.0.0 network is displayed.
Answer: A
Explanation:
Explanation
For an EIGRP neighbor to form, the following must match:
- Neighbors must be in the same subnet
- K values
- AS numbers
- Authentication method and key strings
Here, we see that R4 is configured for EIGRP AS 2, when it should be AS 1.

NEW QUESTION: 3
systemdに含まれるどのコマンドが、時間やユニット名などの基準によってsystemdジャーナルからのメッセージの選択をサポートしますか？ （パスまたはパラメーターなしでコマンドのみを指定します。）
Answer:
Explanation:
journalctl

NEW QUESTION: 4
__________ And __________ are used to classify and organize services within a service inventory.
A. service compositions, service-oriented solutions
B. service contracts, service capabilities
C. service capabilities, service compositions
D. service models, service layers
Answer: D