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NEW QUESTION: 1
Which of the following statements is true about ARP?
A. ARP is encapsulated in Ethernet packets.
B. Inverse ARP is used to resolve device names.
C. ARP can be deployed on PPP and HDLC links.
D. The MAC address and UUID of the destination end can be obtained through ARP.
Answer: A

NEW QUESTION: 2
Refer to the exhibit.

If router R1 is configured to run IS-IS with given configuration and all interfaces are up/up, what action must you take so that the Ethernet 0/0 netwrok can be advertised to potential IS-IS neighbors on the E0/1 interface?
A. Add the network 10.10.30.1 0.0.0.0 command to the R1 IS-IS process.
B. Configure the ip router isis command on R1's interface E0/1.
C. Add the network 10.10.20.1 0.0.0.0 command to the R1 IS-IS process.
D. Configure an NSAP address on R1.
Answer: B

NEW QUESTION: 3
単一のCloud SQLインスタンスを使用して、特定のゾーンからアプリケーションを提供しています。高可用性を導入する必要があります。あなたは何をするべきか？
A. 同じリージョンで異なるゾーンにフェイルオーバーレプリカインスタンスを作成します
B. 別のリージョンにリードレプリカインスタンスを作成します
C. 異なる地域にフェールオーバーレプリカインスタンスを作成する
D. 同じリージョンで異なるゾーンにリードレプリカインスタンスを作成します
Answer: A

NEW QUESTION: 4
Refer to the exhibit. The network is converged.After link-state advertisements are received from Router_A, what information will Router_E contain in its routing table for the subnets 208.149.23.64 and
208.149.23.96?

A. 208.149.23.64[110/1] via 190.172.23.10, 00:00:07, Serial1/0 208.149.23.96[110/3] via 190.173.23.10,
00:00:16, FastEthemet0/0
B. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, FastEthemet0/0 208.149.23.96[110/13] via
190.173.23.10, 00:00:16, FastEthemet0/0
C. 208.149.23.64[110/3] via 190.172.23.10, 00:00:07, Serial1/0 208.149.23.96[110/3] via 190.173.23.10,
00:00:16, Serial1/0
D. 208.149.23.64[110/13] via 190.173.23.10, 00:00:07, Serial1/0 208.149.23.96[110/13] via
190.173.23.10,
00:00:16, Serial1/0 208.149.23.96[110/13] via 190.173.23.10, 00:00:16, FastEthemet0/0
Answer: B
Explanation:
Explanation/Reference:
Explanation:
Router_E learns two subnets subnets 208.149.23.64 and 208.149.23.96 via Router_A through FastEthernet interface. The interface cost is calculated with the formula 108 / Bandwidth. For FastEthernet it is 108 / 100 Mbps = 108 / 100,000,000 = 1. Therefore, the cost is 12 (learned from Router_A) + 1 = 13 for both subnets ->
The cost through T1 link is much higher than through T3 link (T1 cost = 108 / 1.544 Mbps = 64; T3 cost
108 / 45 Mbps = 2) so surely OSPF will choose the path through T3 link -> Router_E will choose the path from Router_A through FastEthernet0/0, not Serial1/0. In fact, we can quickly eliminate answers B, C and D because they contain at least one subnet learned from Serial1/0 -> they are surely incorrect.