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NEW QUESTION: 1
What method should you use to deploy servers?
Fallstudientitel (Case Study):


A. AIK
B. ADK
C. EDT
D. WDS
Answer: D
Explanation:
Explanation/Reference:
http://technet.microsoft.com/en-us/library/hh974416.aspx

NEW QUESTION: 2
シスコやその他の業界組織が既知のセキュリティ上の発見や脆弱性を公開してユーザーに通知する場合、どの名前が使用されますか？
A. 一般的な脆弱性、エクスプロイト、脅威
B. 一般的な脆弱性とエクスポージャー
C. 一般的なセキュリティエクスプロイト
D. 一般的なエクスプロイトと脆弱性
Answer: B
Explanation:
Explanation
https://www.cisco.com/c/en/us/td/docs/ios-xml/ios/cve/174/cve-addressed-1741.html

NEW QUESTION: 3
You are a database developer for an application hosted on a Microsoft SQL Server 2012 server.
The database contains two tables that have the following definitions:

Global customers place orders from several countries.
You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. SELECT CustomerID, CustomerName, ShippingCountry
FROM
(SELECT c.CustomerID, c.CustomerName,
o. ShippingCountry,
RANK() OVER (PARTITION BY c. CustomerID
ORDER BY o. OrderAmount DESC) AS Rnk
FROM Customer c
INNER JOIN Orders o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName,
o.ShippingCountry) cs
WHERE Rnk = 1
B. SELECT CustomerID, CustomerName, ShippingCountry
FROM
(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry,
RANK() OVER (PARTITION BY c.CustomerID
ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk
FROM Customer c
INNER JOIN Orders o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName,
o.ShippingCountry) cs
WHERE Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
COUNT(OrderAmount) AS OrderAmount
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
ORDER BY OrderAmount DESC
D. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(OrderAmount) DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
Where o.Rnk = 1
Answer: A