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NEW QUESTION: 1
The RSA Algorithm uses which mathematical concept as the basis of its encryption?
A. 16-round ciphers
B. Two large prime numbers
C. Geometry
D. PI (3.14159...)
Answer: B
Explanation:
Explanation/Reference:
Source: TIPTON, et. al, Official (ISC)2 Guide to the CISSP CBK, 2007 edition, page 254.
And from the RSA web site, http://www.rsa.com/rsalabs/node.asp?id=2214 :
The RSA cryptosystem is a public-key cryptosystem that offers both encryption and digital signatures (authentication). Ronald Rivest, Adi Shamir, and Leonard Adleman developed the RSA system in 1977
[RSA78]; RSA stands for the first letter in each of its inventors' last names.
The RSA algorithm works as follows: take two large primes, p and q, and compute their product n = pq; n is called the modulus. Choose a number, e, less than n and relatively prime to (p-1)(q-1), which means e and (p-1)(q-1) have no common factors except 1. Find another number d such that (ed - 1) is divisible by (p-1)(q-1). The values e and d are called the public and private exponents, respectively. The public key is the pair (n, e); the private key is (n, d). The factors p and q may be destroyed or kept with the private key.
It is currently difficult to obtain the private key d from the public key (n, e). However if one could factor n into p and q, then one could obtain the private key d. Thus the security of the RSA system is based on the assumption that factoring is difficult. The discovery of an easy method of factoring would "break" RSA (see Question 3.1.3 and Question 2.3.3).
Here is how the RSA system can be used for encryption and digital signatures (in practice, the actual use is slightly different; see Questions 3.1.7 and 3.1.8):
Encryption
Suppose Alice wants to send a message m to Bob. Alice creates the ciphertext c by exponentiating: c = me mod n, where e and n are Bob's public key. She sends c to Bob. To decrypt, Bob also exponentiates:
m = cd mod n; the relationship between e and d ensures that Bob correctly recovers m. Since only Bob knows d, only Bob can decrypt this message.
Digital Signature
Suppose Alice wants to send a message m to Bob in such a way that Bob is assured the message is both authentic, has not been tampered with, and from Alice. Alice creates a digital signature s by exponentiating: s = md mod n, where d and n are Alice's private key. She sends m and s to Bob. To verify the signature, Bob exponentiates and checks that the message m is recovered: m = se mod n, where e and n are Alice's public key.
Thus encryption and authentication take place without any sharing of private keys: each person uses only another's public key or their own private key. Anyone can send an encrypted message or verify a signed message, but only someone in possession of the correct private key can decrypt or sign a message.

NEW QUESTION: 2
Java例外メカニズムの利点はどれですか? (3つ選択してください。)
A. 例外は発生したメソッドで処理する必要があるため、プログラム構造を改善します。
B. プログラマーが例外を処理する場所を選択できるため、プログラム構造が改善されます。
C. 作成中の特定のプログラムにカスタマイズされた新しい例外の作成を許可します
D. エラー処理コードが通常のプログラム機能から分離されているため、プログラム構造が改善されます。
E. 考えられるすべてのエラーをカバーする一連の標準例外を提供します
Answer: B,C,D

NEW QUESTION: 3



A. Option A
B. Option D
C. Option B
D. Option C
Answer: D
Explanation:
The command "distribute-list 10 in Serial0 will create an incoming distribute list for interface serial 0 and refers to access list 10. So it will permit routing updates from 10.0.x.x network while other entries (in this case the 10.1.0.0/24 and 172.24.1.0/24 networks) will be filtered out from the routing update received on interface S0.

NEW QUESTION: 4
You need to ensure that least cost routing is used in the Los Angeles and Houston offices for local calls after the gateway is deployed. The solution must meet the technical requirements.
Which route should you assign to each public switched telephone network (PSTN) usage?
To answer, drag the appropriate route to the correct PSTN usage in the answer area. Each route may be used once, more than once, or not at all. Additionally, you may need to drag the split bar between panes or scroll to view content.

Answer:
Explanation:

Explanation


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