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NEW QUESTION: 1
데이터 과학자는 고속의 실시간 스트리밍 데이터를 위한 서버리스 수집 및 분석 솔루션을 만들어야 합니다.
수집 프로세스는 수신 레코드를 JSON에서 버퍼링하고 데이터 손실없이 쿼리에 최적화 된 열 형식으로 변환해야 합니다. 출력 데이터 저장소는 가용성이 높아야 하며 분석가는 데이터에 대해 SQL 쿼리를 실행하고 기존 비즈니스 인텔리전스 대시 보드에 연결할 수 있어야 합니다.
데이터 과학자가 요구 사항을 충족시키기 위해 어떤 솔루션을 구축해야 합니까?
A. Amazon Kinesis Data Analytics를 사용하여 스트리밍 데이터를 수집하고 실시간 SQL 쿼리를 수행하여 Amazon S3에 제공하기 전에 레코드를 Apache Parquet로 변환합니다. 분석가가 Amazon Athena를 사용하여 Amazon S3에서 직접 데이터를 쿼리하고 Athena JDBC (Java Database Connectivity) 커넥터를 사용하여 Bl 도구에 연결하도록 하십시오.
B. 각 JSON 레코드를 Amazon S3의 준비 위치에 씁니다. S3 Put 이벤트를 사용하면 데이터를 Apache Parquet 또는 ORC 형식으로 변환하고 Amazon S3의 처리된 데이터 위치에 데이터를 쓰는 AWS Lambda 함수를 트리거 할 수 있습니다. 분석가가 Amazon Athena를 사용하여 Amazon S3에서 직접 데이터를 쿼리하고 Athena JDBC (Java Database Connectivity) 커넥터를 사용하여 Bl 도구에 연결하도록 하십시오.
C. AWS Glue Data Catalog에서 수신 데이터 형식의 스키마를 생성합니다. Amazon S3로 전송하기 전에 Amazon Kinesis Data Firehose 전송 스트림을 사용하여 AWS Glue Data Catalog를 사용하여 데이터를 스트리밍하고 Apache Parquet 또는 ORC 형식으로 데이터를 변환하십시오. 분석가가 Amazon Athena를 사용하여 Amazon S3에서 직접 데이터를 쿼리하고 Athena JDBC (Java Database Connectivity) 커넥터를 사용하여 Bl 도구에 연결하도록하십시오.
D. 각 JSON 레코드를 Amazon S3의 준비 위치에 씁니다. S3 Put 이벤트를 사용하여 데이터를 Apache Parquet 또는 ORC 형식으로 변환하고 Amazon RDS PostgreSQL 데이터베이스에 삽입하는 AWS Lambda 함수를 트리거하십시오. 분석가가 RDS 데이터베이스에서 대시 보드를 쿼리하고 실행하도록 합니다.
Answer: C

NEW QUESTION: 2
You are installing Avaya Contact Center Control Manager (ACCCM).
What are your options for frequency of synchronization in configuring the Synchronizer Service Interval?
A. monthly, weekly, daily
B. daily, or the number of seconds you select
C. dally, hourly, or half-hourly
D. weekly,daily,hourly
E. dally, orthe number of minutes you select
Answer: C

NEW QUESTION: 3
View the Exhibit and examine the structure of the ORDER_ITEMS table. You need to display the ORDER_ID of the order that has the highest total value among all the
orders in the ORDER_ITEMS table. Which query would produce the desired output?
ORDER ITEMS

A. SELECT order_id FROM order_items
WHERE (unit_price*quantity) = (SELECT MAX(unit_price*quantity) FROM order_items GROUP
BY order_id);
B. SELECT order_id FROM order_items GROUP BY order_id
HAVING SUM(unit_price*quantity) =(SELECT MAX(SUM(unit_price*quantity)j FROM
order_items GROUP BY order_id);
C. SELECT order_id FROM order_items
WHERE(unit_price*quantity) = MAX(unit_price*quantity) GROUP BY order_id;
D. SELECT order_id FROM order_items
WHERE(unit_price*quantity) = (SELECT MAX(unit_price*quantity) FROM order_items) GROUP
BY order_id;
Answer: B