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NEW QUESTION: 1
Joe, a company's network engineer, is concerned that protocols operating at the application layer of the OSI model are vulnerable to exploitation on the network. Which of the following protocols should he secure?
A. ICMP
B. SNMP
C. NetBIOS
D. SSL
Answer: B

NEW QUESTION: 2
The NetScaler logging client server can be installed and configured to store the log for ___________. (Choose the correct option to complete the sentence.)
A. HTTP and HTTPS active connections on the NetScaler
B. statistics of the HTTP and HTTPS web sites load balanced on NetScaler
C. HTTP and HTTPS requests processed by the NetScaler
D. status of all the HTTP and HTTPS backend web servers
Answer: C

NEW QUESTION: 3
SQL Server 2014 Enterprise Editionを使用している。
データベースにAuditDataという名前のパーティションテーブルが含まれています。 AuditDataは年ごとに分割されています。 パーティション1には、2010年以前のデータが含まれています。
経営陣は、2010年以前のすべてのAUDITDATAレコードをアーカイブすることを決定しました。
経営陣は、レコードをデータベースから完全に削除し、zip形式のテキストファイルとしてバックアップチームに提供することを望んでいます。 データはもうデータベースに存在してはいけません。
環境のパフォーマンス低下に対する許容度はほとんどありません。 最小限のシステムリソースを使用して、AuditDataテーブルから2010年以前のデータをすべて削除する必要があります。 必要なSQLアクションを正しい順序で選択して配置して、ソリューションを開発してください。
あなたはすべての行動を必要としないかもしれません。

Answer:
Explanation:

Explanation

Note:
- Create a new partitioned table with the partition function you want, and then insert the data from the old table into the new table by using an INSERT INTO...SELECT FROM statement.
- SPLIT RANGE ( boundary_value )
Adds one partition to the partition function. boundary_value determines the range of the new partition, and must differ from the existing boundary ranges of the partition function. Based on boundary_value, the Database Engine splits one of the existing ranges into two.
Of these two, the one where the new boundary_value resides is considered the new partition.
- BCP can be used top produce the zipped text file.
- Example: plitting a partition of a partitioned table or index into two partitions The following example creates a partition function to partition a table or index into four partitions.
ALTER PARTITION FUNCTION splits one of the partitions into two to create a total of five partitions.
CREATE PARTITION FUNCTION myRangePF1 (int)
AS RANGE LEFT FOR VALUES ( 1, 100, 1000 );
GO
-Split the partition between boundary_values 100 and 1000
-to create two partitions between boundary_values 100 and 500
--and between boundary_values 500 and 1000.
ALTER PARTITION FUNCTION myRangePF1 ()
SPLIT RANGE (500);

NEW QUESTION: 4

A. Option E
B. Option A
C. Option C
D. Option D
E. Option B
Answer: C,D