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NEW QUESTION: 1

A. Update-AdfsRelyingPartyTrust
B. Set-AdfsProperties
C. Invoke-AdfsFarmBehaviorLevelRaise
D. Set-AdfsFarmInformation
Answer: C
Explanation:
AD FS for Windows Server 2016 introduces the ability to have separation between server administrators and AD FS service administrators.
After upgrading our ADFS servers to Windows Server 2016, the last step is to raise the
Farm Behavior Level using the Invoke-AdfsFarmBehaviorLevelRaise PowerShell cmdlet.
To upgrade the farm behavior level from Windows Server 2012 R2 to Windows Server
2016 use the Invoke-ADFSFarmBehaviorLevelRaise cmdlet.
References: https://technet.microsoft.com/en-us/library/mt605334(v=ws.11).aspx

NEW QUESTION: 2
You have an Active Directory domain named Adatum.com that is synchronized to Azure Active Directory as shown in the exhibit.

Use the drop-down menus to select the answer choice that completes each statement based on the information presented in the graphic.
NOTE: Each correct selection is worth one point.

Answer:
Explanation:

Explanation

Group Writeback is enabled in the Azure AD Connect configuration so groups created in Azure Active Directory will be synchronized to the on-premise Active Directory. A security group created in Azure Active Directory will be synchronized to the on-premise Active Directory as a security group.
Device Writeback is enabled in the Azure AD Connect configuration so computers joined to the Azure Active Directory will be synchronized to the on-premise Active Directory. They will sync to the RegisteredDevices container in the on-premise Active Directory.
Reference:
https://docs.microsoft.com/en-us/azure/active-directory/hybrid/how-to-connect-device-writeback

NEW QUESTION: 3
Which two statements describe the IP address 10.16.3.65/23? (Choose two.)
A. The network is not subnetted.
B. The broadcast address of the subnet is 10.16.3.255 255.255.254.0.
C. The subnet address is 10.16.3.0 255.255.254.0.
D. The last valid host address in the subnet is 10.16.2.254 255.255.254.0
E. The lowest host address in the subnet is 10.16.2.1 255.255.254.0.
Answer: B,E
Explanation:
Explanation
The mask 255.255.254.0 (/23) used with a Class A address means that there are 15 subnet bits and 9 host bits.
The block size in the third octet is 2 (256 - 254). So this makes the subnets in 0, 2, 4, 6, etc., all the way to
254. The host 10.16.3.65 is in the 2.0 subnet. The next subnet is 4.0, so the broadcast address for the 2.0 subnet is 3.255. The valid host addresses are 2.1 through 3.254

NEW QUESTION: 4
What are the four replicated database rings in a cluster? (choose four)
A. virtual-interface manager (vifmgr)
B. management application (mgmt)
C. SAN management deamon (bcomd)
D. administrator
E. volume location database (vldb)
F. logical-interface manager (lifmgr)
G. protocol management daemon (prtodb)
Answer: A,B,C,E
Explanation:
https://library.netapp.com/ecmdocs/ECMP1196798/html/GUID-C8F1D8ED-7420-48CC-8CC8FF0A80399AA0.html