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NEW QUESTION: 1
TRANSACTIONSテーブルの説明を調べます。

どの2つのSQLステートメントが正常に実行されますか？
A. SELECT customer_id AS 'CUSTOMER-ID'、transaction_date AS DATE、amount + 100 'DUES' FROM transaction;
B. SELECT customer_id AS "CUSTOMER-ID"、transaction_date AS DATE、amount + 100 "DUES" FROM transaction;
C. SELECT customer_id AS "CUSTOMER-ID"、transaction_date AS "DATE"、amount + 100 DUES FROM transaction;
D. SELECT customer_id AS CUSTOMER-ID、transaction_date AS TRANS_DATE、amount + 100 "DUES AMOUNT" FROMトランザクション;
E. SELECT customer_id CUSTID、transaction_date TRANS_DATE、金額+100 DUES FROMトランザクション。
Answer: C,E

NEW QUESTION: 2
次のうちどれが行政統制と見なされますか？
A. キーストロークロギング
B. ドアロック
C. アクセス制御プロセス
D. 生体認証
Answer: C
Explanation:
説明
プロセスは管理上の制御です。プロセスには他のタイプの制御の要素が含まれる場合があります（この場合、アクセス制御メカニズムは技術的な制御である場合もあれば、物理的な制御である場合もあります）が、プロセス自体は管理上のものです。キーストロークロギングは技術的なコントロールです（悪意のある目的で行われ、監査ではない場合は攻撃です）。ドアロックは物理的な制御です。生体認証は技術的な制御です。

NEW QUESTION: 3
HOTSPOT
Corporate headquarters provided your office a portion of their class B subnet to use at a new office location. Allocate the minimum number of addresses (using CIDR notation) needed to accommodate each department.

After accommodating each department, identify the unused portion of the subnet by responding to the question on the graphic. All drop downs must be filled.
Instructions: When the simulation is complete, please select the Done button to submit.


All Networks have the range from /0 to/32
Answer:
Explanation:

Explanation:
An IPv4 address consists of 32 bits. The first x number of bits in the address is the network address and the remaining bits are used for the host addresses. The subnet mask defines how many bits form the network address and from that, we can calculate how many bits are used for the host addresses.
The formula to calculate the number of hosts in a subnet is 2n - 2. The "n" in the host's formula represents the number of bits used for host addressing. If we apply the formula (22 - 2), we can determine that the following subnets should be configured:
Sales network - /26 - This will provide up to 62 usable IP addresses (64-2 for subnet and broadcast IP)
HR network - /27 - This will provide for up to 30 usable IP's (32-2)
IT - /28 - This will provide for up to 14 usable IP's (16-2)
Finance - /26 - Note that a /27 is 32 IP addresses but 2 of those are reserved for the network and
broadcast IP's and can't be used for hosts.
Marketing - /28
If we add up how many IP blocks are used that is 64+32+16+64+16=192.
A /24 contains 256 IP addresses, so 256-192=64.
So the last unused box should be a /26, which equates to 64 addresses

NEW QUESTION: 4
Which /etc/hosts.allow entries will permit access to sshd for users from the 192.168.1.0/24 subnet? (Choose TWO correct answers.)
A. sshd : 192.168.1.0
B. sshd : 192.168.1
C. sshd : 192.168.1.
D. sshd : 192.168.1.0/255.255.255.0
E. sshd : 192.168.1.0 netmask 255.255.255.0
Answer: C,D