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NEW QUESTION: 1
Select three components of the integration gateway. (Choose three.)
A. Listening connectors
B. Target connectors
C. Transformation engine
D. Performance throttling
E. Data handling dispatchers and handlers
F. XML Parsing
Answer: A,B,F

NEW QUESTION: 2
DRAG DROP




Answer:
Explanation:

Explanation:
Target 1: from
Target 2: join
Target 3: on
Target 4: equals
Example: Join operations create associations between sequences that are not explicitly modeled in the data sources. For example you can perform a join to find all the customers and distributors who have the same location. In LINQ the join clause always works against object collections instead of database tables directly.
C#
var innerJoinQuery
from cust in customers
join dist in distributors on cust.City equals dist.City
select new { CustomerName = cust.Name, DistributorName = dist.Name };

NEW QUESTION: 3

A. Option D
B. Option C
C. Option B
D. Option A
Answer: D
Explanation:
Ref:https://technet.microsoft.com/en-us/library/dn832103.aspx https://technet.microsoft.com/enus/library/dn531187.aspx#BKMK_UsingTheRightTypeOfNumber

NEW QUESTION: 4
View the Exhibit and examine the structure of the EMPLOYEES table.
You want to display all employees and their managers having 100 as the MANAGER_ID. You want the output in two columns: the first column would have the LAST_NAME of the managers and the second column would have LAST_NAME of the employees.
Which SQL statement would you execute?

A. SELECT m.last_name "Manager", e.last_name "Employee"
FROM employees m JOIN employees e
WHERE m.employee_id = e.manager_id AND e.manager_id=100;
B. SELECT m.last_name "Manager", e.last_name "Employee"
FROM employees m JOIN employees e
ON m.employee_id = e.manager_id
WHERE e.manager_id=100;
C. SELECT m.last_name "Manager", e.last_name "Employee"
FROM employees m JOIN employees e
ON e.employee_id = m.manager_id
WHERE m.manager_id=100;
D. SELECT m.last_name "Manager", e.last_name "Employee"
FROM employees m JOIN employees e
ON m.employee_id = e.manager_id
WHERE m.manager_id=100;
Answer: B