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NEW QUESTION: 1
다음 중 총 품질 관리를 성공적으로 수행하기 위한 열쇠는 무엇입니까?
A. 명확하게 정의 된 품질 표준을 확립 한 후 이를 충족시키는 데 중점을 둡니다.
B. 고객에 집중합니다.
C. 효율성을 높이기 위해 적절한 계층을 만듭니다.
D. 교육 품질 검사원.
Answer: B
Explanation:
TOM emphasizes satisfaction of customers, both internal and external. TOM considers the supplier's relationship with the customer, identifies customer needs, and recognizes that everyone in a process is at some time a customer or supplier of someone else, either inside or outside of the organization. Thus, TOM begins with external customer requirements, identifies internal customer-supplier relationships and requirements, and establishes requirements for external suppliers.

NEW QUESTION: 2
Relative to a capital lease, an operating lease will result in:
A. Higher interest expenses early in the lease.
B. Higher profits reported in the early years of the lease.
C. Higher total assets and reported liabilities.
Answer: B

NEW QUESTION: 3
A systems administrator is attempting to recover from a catastrophic failure in the datacenter.
To recover the domain controller, the systems administrator needs to provide the domain administrator credentials.
Which of the following account types is the system administrator using?
A. User account
B. Guest account
C. Shared accounts
D. Service account
Answer: D

NEW QUESTION: 4
A programmer must create a generic class MinMax and the type parameter of MinMax must implement Comparable. Which implementation of MinMax will compile?
A. class MinMax<E extends Comparable<E>> {
<E>
E min = null;
<E>
E max = null;
public MinMax() {}
public <E> void put(E value) { /* store min or max */ }
B. class MinMax<E implements Comparable<E>> {
<E>
E min = null;
<E>
E max = null;
public MinMax() {}
public <E> void put(E value) { /* store min or max */ }
C. class MinMax<E extends Comparable<E>> {
E min = null;
E max = null;
public MinMax() {}
public void put(E value) { /* store min or max */ }
D. class MinMax<E implements Comparable<E>> {
E min = null;
E max = null;
public MinMax() {}
public void put(E value) { /* store min or max */ }
Answer: C